Labelled Experiment with Two Status Quo

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Re: Labelled Experiment with Two Status Quo

Postby arfawikurdhi » Mon Aug 05, 2019 8:57 pm

Dear Prof. Bliemer

I keep ascA_new and priceA=priceB=price. Could you please give me your opinion?

Design
;alts = brandA_refurb, brandB_refurb, brandA_new, brandB_new
;rows = 20
;block = 2
;eff = (mnl,d)
;con
;model:
U(brandA_refurb) = ascA_refurb
+ condition*condition[0,1]
+ discount_linearA*discountreb[0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,0.95]*pricenewA[600]
+ discount_quadraticA*discountreb*discountreb*pricenewA /
U(brandB_refurb) = condition*condition
+ discount_linearB*discountreb*pricenewB[480]
+ discount_quadraticB*discountreb*discountreb*pricenewB /
U(brandA_new) = ascA_new
+ price*pricenewA/
U(brandB_new) = price*pricenewB
$

Thank you so much.

Kindly regards,
Arfa
arfawikurdhi
 
Posts: 7
Joined: Tue May 21, 2019 4:21 am
Location: The Netherland

Re: Labelled Experiment with Two Status Quo

Postby arfawikurdhi » Mon Aug 05, 2019 9:06 pm

Dear Prof. Bliemer

I keep ascA_new and priceA=priceB=price. Could you please give me your opinion?

Design
;alts = brandA_refurb, brandB_refurb, brandA_new, brandB_new
;rows = 20
;block = 2
;eff = (mnl,d)
;con
;model:
U(brandA_refurb) = ascA_refurb
+ condition*condition[0,1]
+ discount_linearA*discountreb[0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,0.95]*pricenewA[600]
+ discount_quadraticA*discountreb*discountreb*pricenewA /
U(brandB_refurb) = condition*condition
+ discount_linearB*discountreb*pricenewB[480]
+ discount_quadraticB*discountreb*discountreb*pricenewB /
U(brandA_new) = ascA_new
+ price*pricenewA/
U(brandB_new) = price*pricenewB
$

Thank you so much.

Kindly regards,
Arfa
arfawikurdhi
 
Posts: 7
Joined: Tue May 21, 2019 4:21 am
Location: The Netherland

Re: Labelled Experiment with Two Status Quo

Postby Michiel Bliemer » Mon Aug 05, 2019 9:07 pm

This is an identifiable model and I think that it makes sense.

Michiel
Michiel Bliemer
 
Posts: 1705
Joined: Tue Mar 31, 2009 4:13 pm

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