Number or rows in design with a status-quo alternative
Posted: Wed Mar 05, 2014 7:32 pm
Dear all,
I'm trying to generate an unlabelled design with 2 alternatives, each with 5 (non-linear) attributes of 5 levels + the status-quo(SQ) alternative. As you can see in my syntax below (all priors are set to 0 because this is a pilot), I have specified the utility of the SQ to be given by a constant and have included this constant in the AVC matrix for the computation of the efficiency measures. So, here is my question: Shall I count the SQ alternative as an independent choice observation-which implies that I need 9 rows in order to estimate my 17 parameters- or not, which in turn means I need 17 rows for my 17 parameters??
My intuition is to include them, since If we can calculate the choice probability of, let's say the first alternative and the status-quo, we can determine the probability for the second alternative. However, I'm not sure since SQ provides no information about the tradeoffs between the attributes.
Best Regards,
Achilleas
I'm trying to generate an unlabelled design with 2 alternatives, each with 5 (non-linear) attributes of 5 levels + the status-quo(SQ) alternative. As you can see in my syntax below (all priors are set to 0 because this is a pilot), I have specified the utility of the SQ to be given by a constant and have included this constant in the AVC matrix for the computation of the efficiency measures. So, here is my question: Shall I count the SQ alternative as an independent choice observation-which implies that I need 9 rows in order to estimate my 17 parameters- or not, which in turn means I need 17 rows for my 17 parameters??
My intuition is to include them, since If we can calculate the choice probability of, let's say the first alternative and the status-quo, we can determine the probability for the second alternative. However, I'm not sure since SQ provides no information about the tradeoffs between the attributes.
- Code: Select all
Design
;alts = alt1, alt2, SQ
;rows=????
;eff = (mnl,d)
;con
;model:
U(alt1) =b2.dummy[0|0|0|0] * X1[1,2,3,4,5] + b3.dummy[0|0|0|0] *X2[1,2,3,4,5] +
b4.dummy[0|0|0|0]*X3[1,2,3,4,5]+b5.dummy[0|0|0|0]*X4[1,2,3,4,5] /
U(alt2) =b2.dummy * X1 + b3.dummy *X2 +b4.dummy*X3+b5.dummy*X4 /
U(SQ)=b1[0] $
Best Regards,
Achilleas