sample size in orthogonal design
Posted: Wed Dec 28, 2011 1:10 am
Hi all,
I have ran the following orth desing (see (2) below) for a pilot phase of a new study (I had few priors from previuos study and for some param. I knew only the sign)
I received only 1 design which looks fine but what bothers me is that
in the MNL efficiency measures (see (1) below) I recieve a huge sample size: S estimate equals: 54,432,463
is it an indication that the design is infeasible?
MNL efficiency measures
D error 0.272616
A error 2.635671
B estimate 99.676321
S estimate 54432463.607656
Prior b2 b3(d0) b3(d1) b3(d2) b4 b5(d0) b6
Fixed prior value -0.1 0 0 0 0.1 0 -0.001
Sp estimates 1474.660861 Undefined Undefined Undefined 21.259181 Undefined 54432463.607656
Sp t-ratios 0.05104 0 0 0 0.425092 0 0.000266
(2)Design
;alts = alt1, alt2, alt3, alt4
;rows=128
;orth=sim
;block=16
;model:
U(alt1) = b2[-0.1]*price[.091,0.117,0.143,0.169,0.196,0.222,0.248,0.274] +b3.dummy[-0|-0|-0]*airline[0,1,2,3]
+b4[0.1]*direct[0,1] +b5.dummy*jet[0,1] +b6[-0.001]*risk[0.1, 0.02, 0.01, 0.0067,0.005,0.004,0.002,0.001] /
U(alt2) = b2*price + b3*airline+ b4*direct+ b5*jet+ b6*risk/
U(alt3) = b2*price + b3*airline+ b4*direct+ b5*jet+ b6*risk/
U(alt4)= b1
Best,
Anat
I have ran the following orth desing (see (2) below) for a pilot phase of a new study (I had few priors from previuos study and for some param. I knew only the sign)
I received only 1 design which looks fine but what bothers me is that
in the MNL efficiency measures (see (1) below) I recieve a huge sample size: S estimate equals: 54,432,463
is it an indication that the design is infeasible?
MNL efficiency measures
D error 0.272616
A error 2.635671
B estimate 99.676321
S estimate 54432463.607656
Prior b2 b3(d0) b3(d1) b3(d2) b4 b5(d0) b6
Fixed prior value -0.1 0 0 0 0.1 0 -0.001
Sp estimates 1474.660861 Undefined Undefined Undefined 21.259181 Undefined 54432463.607656
Sp t-ratios 0.05104 0 0 0 0.425092 0 0.000266
(2)Design
;alts = alt1, alt2, alt3, alt4
;rows=128
;orth=sim
;block=16
;model:
U(alt1) = b2[-0.1]*price[.091,0.117,0.143,0.169,0.196,0.222,0.248,0.274] +b3.dummy[-0|-0|-0]*airline[0,1,2,3]
+b4[0.1]*direct[0,1] +b5.dummy*jet[0,1] +b6[-0.001]*risk[0.1, 0.02, 0.01, 0.0067,0.005,0.004,0.002,0.001] /
U(alt2) = b2*price + b3*airline+ b4*direct+ b5*jet+ b6*risk/
U(alt3) = b2*price + b3*airline+ b4*direct+ b5*jet+ b6*risk/
U(alt4)= b1
Best,
Anat