Number of choice tasks for DCE
Posted: Thu Jan 17, 2019 11:48 am
Dear all
I’m still an Ngene novice and hoped for some advice/help please regarding working out the number of choice tasks (S) for my DCE.
I intend to analyse data collected from a DCE using panel mixed multinomial logit model (MMNL).
I know that with Ngene, even though I will be analysing using panel mixed multinomial logit model (MMNL), I can still design choice tasks using a multinomial logit (MNL) model.
So using the MNL model for designing DCE, I have:
11 parameter coefficients i.e. K=11
J=3 so (J-1)=(3-1)=2
minimum number of choice tasks (S) = S >= K÷(J-1)
so S >= 11÷2 = minimum of 6 choice tasks for my DCE.
However, as I will be analysing collected data using a panel mixed multinomial logit model (MMNL) and I will be estimating a mean and standard deviation for each coefficient, this increases the number of parameters. Usually, this means doubling the minimum number of choice tasks required (S).
1). So I should double my minimum number of choice tasks to a minimum of 12 choice tasks for my DCE?
2). As we shouldn’t use the bare minimum number of choice tasks, does that mean that I should again double my minimum number of choice tasks (i.e. 12 x 2)?
3). Does that mean that I should be using 24 choice tasks for my DCE?
Apologies for the simple, silly questions.
Thanks,
Rakhee.
I’m still an Ngene novice and hoped for some advice/help please regarding working out the number of choice tasks (S) for my DCE.
I intend to analyse data collected from a DCE using panel mixed multinomial logit model (MMNL).
I know that with Ngene, even though I will be analysing using panel mixed multinomial logit model (MMNL), I can still design choice tasks using a multinomial logit (MNL) model.
So using the MNL model for designing DCE, I have:
11 parameter coefficients i.e. K=11
J=3 so (J-1)=(3-1)=2
minimum number of choice tasks (S) = S >= K÷(J-1)
so S >= 11÷2 = minimum of 6 choice tasks for my DCE.
However, as I will be analysing collected data using a panel mixed multinomial logit model (MMNL) and I will be estimating a mean and standard deviation for each coefficient, this increases the number of parameters. Usually, this means doubling the minimum number of choice tasks required (S).
1). So I should double my minimum number of choice tasks to a minimum of 12 choice tasks for my DCE?
2). As we shouldn’t use the bare minimum number of choice tasks, does that mean that I should again double my minimum number of choice tasks (i.e. 12 x 2)?
3). Does that mean that I should be using 24 choice tasks for my DCE?
Apologies for the simple, silly questions.
Thanks,
Rakhee.