Calculate no. of choice situations (labeled, full factorial)
Posted: Tue Jul 16, 2019 6:33 am
Dear all,
I am reading the Ngene handbook and have a problem understanding the calculation on page 95, referring to Table 7.1.
It is said that "the full factorial design has 2^1 x 3^8 x 4^2 = 209,952 choice situations".
I don't understand how exactly this is calculated, particularly the 3^8 part.
I thought that you would multiply the number of levels, but I really don't get where there are 8 times 3 levels.
Can anybody help me?
Thanks a lot in advance!
I am reading the Ngene handbook and have a problem understanding the calculation on page 95, referring to Table 7.1.
It is said that "the full factorial design has 2^1 x 3^8 x 4^2 = 209,952 choice situations".
I don't understand how exactly this is calculated, particularly the 3^8 part.
I thought that you would multiply the number of levels, but I really don't get where there are 8 times 3 levels.
Can anybody help me?
Thanks a lot in advance!